9m^2=-3m+18

Solution for 9m^2=-3m+18 equation:

9m^2=-3m+18

We move all terms to the left:

9m^2-(-3m+18)=0

We get rid of parentheses

9m^2+3m-18=0

a = 9; b = 3; c = -18;
Δ = b2-4ac
Δ = 32-4·9·(-18)
Δ = 657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{657}=\sqrt{9*73}=\sqrt{9}*\sqrt{73}=3\sqrt{73}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{73}}{2*9}=\frac{-3-3\sqrt{73}}{18}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{73}}{2*9}=\frac{-3+3\sqrt{73}}{18}
$